Question

If a=(2^2*3^3*5^4)and b=(2^3*3^2*5),then find HCF(a,b)

Answer 1

It is given that: 

a = (2² × 3³ × 5⁴ ) and b = (2³ × 3² × 5) 

∴HCF (a,b) = Product of smallest power of each common prime factor in the numbers. 

 = 2² × 3² × 5 

 = 180

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Thankyousomuch

Answer 2

Step-by-step explanation:

The given numbers are

$a=2^2\times 3^3\times 5^4$

$b=2^3\times 3^2\times 5$

Highest Common Factor of a and b :

It is a largest positive integer that divides both a and b.

H.C.F. = 2^2 \times 3^2 \times 5H.C.F.=22×3<span class="" style="disp