# If a=(2^2*3^3*5^4)and b=(2^3*3^2*5),then find HCF(a,b)

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If a=(2^2*3^3*5^4)and b=(2^3*3^2*5),then find HCF(a,b)

by (15.1k points)

It is given that:

a = (22 × 33 × 54 ) and b = (23 × 32 × 5)

∴HCF (a,b) = Product of smallest power of each common prime factor in the numbers.

= 22 × 32 × 5

= 180

by (221 points)
Thankyousomuch
ago by (15 points)

Step-by-step explanation:

The given numbers are

a= 2^2\times 3^3\times 5^4

b=2^3\times 3^2\times 5

Highest Common Factor of a and b :

It is a largest positive integer that divides both a and b.

H.C.F. = 2^2 \times 3^2 \times 5